2sin^2x(x)+5cos(x)+1=0

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Solution for 2sin^2x(x)+5cos(x)+1=0 equation: 


Simplifying
2sin2x(x) + 5cos(x) + 1 = 0

Multiply in2sx * x
2in2sx2 + 5cos(x) + 1 = 0

Multiply cos * x
2in2sx2 + 5cosx + 1 = 0

Reorder the terms:
1 + 5cosx + 2in2sx2 = 0

Solving
1 + 5cosx + 2in2sx2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 5cosx + -1 + 2in2sx2 = 0 + -1

Reorder the terms:
1 + -1 + 5cosx + 2in2sx2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 5cosx + 2in2sx2 = 0 + -1
5cosx + 2in2sx2 = 0 + -1

Combine like terms: 0 + -1 = -1
5cosx + 2in2sx2 = -1

Add '-2in2sx2' to each side of the equation.
5cosx + 2in2sx2 + -2in2sx2 = -1 + -2in2sx2

Combine like terms: 2in2sx2 + -2in2sx2 = 0
5cosx + 0 = -1 + -2in2sx2
5cosx = -1 + -2in2sx2

Divide each side by '5osx'.
c = -0.2o-1s-1x-1 + -0.4in2o-1x

Simplifying
c = -0.2o-1s-1x-1 + -0.4in2o-1x

Reorder the terms:
c = -0.4in2o-1x + -0.2o-1s-1x-1

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